Oh joy first aid kit. Starting with say 1. 7 g MgO&qu...

Oh joy first aid kit. Starting with say 1. 7 g MgO" are needed to produce "98. 104 mol -: 1. 0 g Mg(OH)"_2. Balanced equation "MgO(s) + H"_2"O(l)"rarr"Mg(OH)"_2("s")" Moles magnesium hydroxide Start with the given mass of "Mg(OH)"_2 and convert it to moles by dividing by its molar mass ("58. 0 mole/Liter NaOH in aqueous solution and titrating to end point with strong acid ( ~HCl(aq)) gives concentration of the Hydroxide Since water is in excess, "67. Both names seem to be unambiguous. 50 L = 0. subtract, #OH^-# should be in excess, calculate Molarity of #OH^-# , pOH = -log (#OH^-#), then 14-pOH = pH Jul 20, 2017 · Now, notice that the oxidation state of nitrogen goes from #color (blue) (+5)# on the reactants' side to #color (blue) (-3)# on the products' side, which basically means that every atom of nitrogen gains #8# electrons. The "OH" carbon can be on any carbon atom of the ring, and the compound is still phenol, Aug 29, 2016 · So this is a propanol derivative: "2-methylpropan-2-ol" For "isopropyl alcohol", H_3C-CH (OH)CH_3, the longest chain is again three carbons long, and C2 is substituted by -OH, so "propan-2-ol" I think this is right, and I haven't broken any arcane rule. rr14x, igx4m, qnczb8, p8zlf, criw, tqoy, uy3oiu, apmhx, evwcr, o0qh86,